Page 158 - Math Course 1 (Book 1)
P. 158
Equations with Grouping Symbols
3b = 37.5 Divide each side MO. 5 - L2b
3 3 by 3.
Equations with No
b = 12.5 Simplify.
Solution
Answer The solution is 12.5
Vocabulary A-Z
Let us learn some vocabulary
Your Turn!
Solve Equations with Parentheses Null Set (or empty set)
Solve 4t = 7(t – 3). Check your solution. Two sets that contain no elements in common is the
null set or empty set, shown by the symbol O or {}.
A. –7
{ 1, 3, 5, 7, 9, ... } { 2, 4, 6, 8, 10, ... } = O
B. 1
10 = { }
C. 1
11
D. 7
Let’s Begin
Answer
Use an Equation to Solve a
Problem
Example
Solve 3(p + 5) = 6(p – 2). Check your solution.
GEOMETRY
A. 9 The perimeter of a rectangle is 36 inches. Find
the dimensions if the length is 2 inches greater
B. 8 than three times the width.
C. 2 1 W
3
1
D. 3w + 2
3
Words 2 times the length + 2 times the
width = perimeter
Answer
Variables Let w = the width.
Let 3w + 2 = the length
Equation 2(3w + 2) + 2w = 36
2(3w + 2) + 2w = 36 Write the equation.
6w + 4 + 2w = 36 Use the Distributive
Property.
8w + 4 = 36 Simplify.
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