Page 119 - Math Course 2 (Book 1)
P. 119

Factoring: Polynomials





                MO. 4 - L1b
                                                                                Let’s Begin
                 Solving Equations of the Form

                              ax2  + bx = 0
                                                                  Solve an Equation
                            Vocabulary A-Z
                            Let us learn some vocabulary           Examples



                                                                   Solve (x – 2)(4x – 1) = 0. Check the solution.
               Zero Products Property                              If (x – 2)(4x – 1) = 0, then according to the Zero
                                                                   Product Property, either x – 2 = 0 or 4x – 1 = 0.
               The Zero Product Property simply states that if
               ab = 0, then either a = 0 or b = 0 (or both). A product   (x – 2)(4x – 1) = 0   Original equation
               of factors is zero if and only if one or more of the
               factors is zero.                                    x – 2 = 0  or  4x – 1 = 0   Set each factor equal to
                                    ab = 0                                               zero.
                                  a = 0, b = 0
                                                                          x = 2               4x = 1  Solve each equation.
                             6(0) = 0         0(3) = 0                                x =   1
                      (5 – 5) (0) = 0            –2(–3 + 3) = 0                         4
               Roots                                                   Answer         The roots are 2 and   1
                                                                                                         4
               The solutions of an equation are called the roots of
               the equation.                                       Check            1
                                                                   Substitute 2 and         for x in the original equation.
                                                                                    4
                              (d – 5)(3d + 4) = 0
                  If (d – 5)(3d + 4) = 0, then according to the        (x – 2)(4x – 1) = 0    (x – 2)(4x – 1) = 0
                                                                                                       ?
                                                                                   ?
                   Zero Product Property either d – 5 = 0 or       (2 – 2)(4 • 2 – 1) = 0       –2  4 •      –1 = 0
                                                                                                 1
                                                                                         1
                                  3d + 4 = 0                                             4       4
                                                                                   ?             7     ?
                                                                              (0) (7) = 0      –        (0) = 0
                (d – 5)(3d + 4) = 0          Original Equation                                   4
                                                                                              0 = 0                           0 = 0
                         d – 5 = 0 or 3d + 4 = 0  Set each factor
                                                                                2
                                             equal to zero.        Solve 4y = 12y . Check the solution.
                                                                   Write the equation so that it is of the form ab = 0.
                                 d = 5   3d = –4  Solve each
                                             equation.
                                                                                 2
                                           3                                    4y = 12y        Original equation
                                         d = –
                                           4                               2                     2
                                                 3
                           The roots are 5 and –      .            4y – 12y  = 0           Subtract 12y  from each side.
                                                 4
                                                                   4y(1 – 3y) = 0          Factor the GCF of 4y and
                                                                                         2
                Key Concept                                                               12y , which is 4y.
                                                                   4y = 0 or 1 – 3y =  0   Zero Product Property

                Zero Product Property                                           –3y = –1

                                                                                    1
                Words     If the product of two factors is 0, then at     y = 0               y =   3
                          least one of the factors must be 0.
                                                                                                         1
                                                                                      The roots are 0 and       .
                Symbols For any real numbers a and b, if ab = 0,                                         3  1
                                                                                                            3
                          then either a = 0, b = 0, or both a and b   Answer      Check by substituting 0 and
                          equal zero.                                               for y in the original equation.
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