Page 198 - Math Course 2 (Book 1)
P. 198

Methods of Solving Systems of Equations

           Mo. 6


           Lesson 5
                                                                         Let’s Begin



          KEY CONCEPTS:
          1. Determine the best method for solving         Determine the Best Method
              systems of equations.
          2. Apply systems of linear equations.
                                                            Examples



                                                           FUND-RAISING
         MO. 6 - L5a                                       At a Boy Scout fund-raising dinner, Mr. Jones bought

           Applying Methods of Solving                     2 adult meals and 3 child meals for $23. Mrs.
                                                           Gomez bought 4 adult meals and 2 child meals for
                Systems of Equations                       $34. All adult meals are the same price and all child
                                                           meals are the same price.


         Concept Summary                                   The following system can be used to represent this
                                                           situation.

         Solving Systems of                                Determine the best method to solve the system of
         Equations                                         equations.
             Method           The Best Time to Use         Then solve the system.
                                                           2x + 3y = 23
                           To estimate the solution, since   4x + 2y = 34
         Graphing          graphing usually does not give
                                 an exact solution.        For an exact solution, an algebraic method is
                                                           best. Since neither the coef  cients of x nor the
                           if one of the variables in either   coef  cients of y are 1 or –1, you cannot use the
         Substitution      equation has a coef  cient of 1  substitution method.
                                      or –1
                                                           Since the coef  cients are not the same for either x
                             if one of the variables has   or y, you will need to use elimination with
         Elimination Using   opposite coef  cients in the
         Addition                                          multiplication.
                                  two equations.
                                                           Multiply the f rst equation by –2 so the coef  cients
                             if one of the variables has   of the x-terms are additive inverses. Then add the
         Elimination Using   same coef  cient in the two
         Subtraction                                       equations.
                                    equations.
                                                           2x + 3y = 23    –4x – 6y = –46 Multiply by –2.
                                                           4x + 2y = 34 (+) 4x + 2y = 34
                            if one of the coef  cients are                         –4y = –12 Add the equations.
                              1 or –1and neither of the
         Elimination Using  variables can be eliminated by
         Multiplication                                                      –4y  = –12  Divide each side
                            simply adding or subtracting                     –4    –4   by –4.
                                   the equations

                                                                                 y = 3  Simplify.


         Now substitute 3 for y in either equation to f nd the                4x = 28  Simplify.
         value of x.                                             4x  =  28      Divide each side by 4.
             4x + 2y  = 34    Second equation                    4     4
                                                                           x = 7  Simplify.
           4x + 2(3) = 34     y = 3
                4x + 6 = 34   Simplify.                                     The solution is (7, 3). So, adult
                                                               Answer       meals cost $7 and child meals
         4x + 6 – 6 = 34 – 6  Subtract 6 from each side.
                                                                                      cost $3.

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