Page 63 - Math Course 3 (Book 1)
P. 63

The Quadratic Formula





                SPACE TRAVEL                                       Since a negative number of seconds is not
                                                                   reasonable, use the positive solutions.
                The height H of an object t seconds after it is

                propelled upward with an initial velocity v is
                                   1                                                  Answer
                                       2
                represented by H = –      gt  + vt + h, where g is the
                                   2
                gravitational pull and h is the initial height.      A ball thrown on Mars will stay aloft 5.6 – 2.2
                                                                       or about 3.4 seconds longer than the ball
                 In order to find when the ball hits the ground, you   thrown on Earth. The ball thrown on Europa
                 must find when H = 0. Write two equations to        will stay aloft 15.6 – 2.2 or about 13.4 seconds
                 represent the situation on Mars and on Europa.          longer than the ball thrown on Earth.


                 Baseball Thrown on Mars                          Use the Discriminant

                       1
                 H = –       gt  + vt + h
                           2
                       2                                           Example
                       1
                              2
                 0 = –       (3.7)t  + 10t + 2
                       2
                                                                   State the value of the discriminant for
                                                                     2
                          2
                 0 = –1.85t  + 10t + 2                             3x  + 10x = 12. Then determine the number
                                                                   of real roots of the equation.
                 Baseball Thrown on Europa                         Step 1  Rewrite the equation in standard form.
                       1
                                                                     2
                           2
                 H = –       gt  + vt + h                          3x  + 10x = 12               Original equation
                       2
                       1
                                                                     2
                              2
                 0 = –       (1.3)t  + 10t + 2                     3x  + 10x – 12 = 12 – 12     Subtract 12 from
                       2                                                                        each side.
                          2
                 0 = –0.65t  + 10t + 2                             3x  + 10x – 12 = 0           Simplify.
                                                                     2
                 These equations cannot be factored, and
                 completing the square would involve a lot         Step 2  Find the discriminant.
                 of computation.
                                                                    2
                                                                                2
                                                                   b – 4ac = (10)  – 4(3)(–12)    a = 3, b = 10, and
                 To find accurate solutions, use the Quadratic                                  c = –12
                 Formula.     –b ±   b  – 4ac
                                      2
                           t =                                                      = 244        Simplify.
                                        2a
                                                                                   The discriminant is 244. Since
                 Thrown on Mars                                       Answer      the discriminant is positive, the
                                       2
                              –10 ±  10  – 4(–1.85)(2)                             equation has two real roots.
                          =
                                        2(–1.85)
                            –10 ±  114.8
                          =                                        State the value of the discriminant for
                                    –3.7                           4x  – 2x + 14 = 0. Then determine the number
                                                                     2
                         t  ≈ –0.19    or     t ≈ 5.60             of real roots of the equation.

                  Thrown on Europa                                 b  – 4ac = (–2)² – 4(4)(14)     a = 4, b = –2, and
                                                                     2
                                                                                                c = 14
                                       2
                              –10 ±  10  – 4(–0.65)(2)
                          =
                                        2(–0.65)                                    = –220      Simplify.
                            –10 ±  105.2
                          =                                                       The discriminant is –220. Since
                                    –1.3
                                                                      Answer      the discriminant is negative, the
                         t  ≈ –0.20    or     t ≈ 15.6                              equation has no real roots.

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