Page 161 - Math Course 2 (Book 2)
P. 161

Understanding Weighted Averages




               Speed of Two Vehicles
                                                                   Your Turn!
                  Examples                                        Speed of One Vehicle



                RESCUE                                             In the morning, when traffic is light, it takes 30
                                                                   minutes to get to work. The trip is 15 miles through
                A railroad switching operator has discovered       towns. In the afternoon, when traffic is a little
                that two trains are heading toward each other on    heavier, it takes 45 minutes. What is the average
                the same track. Currently, the trains are 53 miles    speed for the round trip?
                apart. One train is traveling at 75 miles per hour
                and the other 40 miles per hour. The faster train   A. 24 miles per hour
                will require 5 miles to stop safely, and the slower   B. 30 miles per hour
                train will require 3 miles to stop safely. About how   C. 15 miles per hour
                many minutes does the operator have to warn the    D. 45 miles per hour
                train engineers to stop their trains?
                                                                     Answer
                Draw a diagram.
                                   53 miles





                   Takes 5                      Takes 3
                 miles to stop                miles to stop


                53 – (5 + 3) = 45 miles left

                Let m = the number of minutes that the operator
                has to warn the train engineers to stop their trains
                safely. Make a table.                             Speed of Two Vehicles
                                   r         t      d = rt         Two students left the school on their bicycles at the

                    Fast Train     75       m        75m           same time, one heading north and the other
                                                                   heading south. The student heading north travels
                   Other Train     40       m        40m           15 miles per hour, and the one heading south

                Write and solve an equation using the information    travels at 17 miles per hour. After about how many
                in the table.                                      minutes will they be 7.5 miles apart?

                Distance           distance
                traveled by        traveled by
                fast train   plus  other train  equals  45 miles.  A. 17 minutes
                                                                   B. 15 minutes
                 75m                  +          40m  =              45  C. 14 minutes
                                                                   D. 30 minutes

                75m + 40m = 45     Original equation

                          115m = 45  Simplify.
                    115m   =  45   Divide each side by 115.
                     115      115                                    Answer
                                   Round to the nearest
                                m ≈ 0.39
                                   hundredth.
                                   Convert to minutes by
                   0.39 x 60 = 23.4
                                   multiplying by 60.
                                  The operator has about 23
                    Answer
                                 minutes to warn the engineers


                                                                                                                  153
   156   157   158   159   160   161   162   163   164   165   166